I created this blog specifically to make this post. It may be the only post I ever write, but since human ignorance is seemingly unbounded, perhaps it won't be.
I thought that today would be a monumental day for this topic. Today, the Mythbusters debuted their long-awaited "Airplane on a treadmill" episode. For years, physics teachers around the world have cringed in horror at heated internet debates concerning a ludicrous thought experiment. Sadly, half of them recoiled in disgust at the correct arguments. Forum posters signed their names with such epithets as "Ph.D. Aerospace Engineer" and "20-year pilot." Somewhat tellingly, these ego-boosters were most often employed by those delivering the wrong answers. Mythbusters finally attempted to end the insanity by performing the experiment themselves.
AND YET...
The debate rages on. Even after being shown seemingly conclusive evidence of the other side's argument, forum-goers from near and far continued to staunchly defend their own theories.
Here and now, the debate will end. I intend this long-winded article to be the definitive answer to the great AOAT conundrum. No further debate is necessary - simply direct the ignorant people to this page, tell them to read it, and let's all get on with answering more intriguing questions, like does P = NP?
For those of you just joining us, "Airplane On A Treadmill," also known as "Airplane on a Conveyor Belt," is a thought experiment in physics. Some consider it a litmus test for assessing one's knowledge of airplane physics. In its most basic form, the experiment is worded thusly:
The question suffers from many rewordings that muddle much of the debate about the thought experiment. The basic idea is that there's a plane, on a treadmill, and we're going to run the treadmill backwards in an attempt to stop the plane from taking off. And here, at the very beginning of this explanation, is the definitive answer. There are in fact two correct answers to this question:
A plane is standing on a large treadmill or conveyor belt. The plane moves in one direction, while the conveyor moves in the opposite direction. This conveyor has a control system that tracks the plane speed and tunes the speed of the conveyor to be exactly the same (but in the opposite direction). Can the plane take off?
-No, the plane can't take off.
-Yes, the plane can take off.
Fooled you! But that's just the point. The experiment is meaningless, and the passionate internet debates more so, if we cannot agree on what is truly meant by the question. But don't worry, I won't pull a Lost on you - I do intend to give a truly airtight answer later on. For now though, we need to debate semantics.
Really, we do.
You see, the AOAT confusion all arises from misses - misconceptions, misinterpretations, and misunderstandings. Consider three rewordings of the question:
1) An airplane is sitting at rest on a very powerful treadmill. You are at the controls of the treadmill, while I am at the controls of the airplane. On some signal, I begin to attempt to take flight in the plane, and you attempt to match my speed to try to keep me stationary. Will the plane take off?
2) An airplane is sitting at rest on a very powerful treadmill. You are at the controls of the treadmill, while I am at the controls of the airplane. On some signal, I throttle up the airplane and you turn on the treadmill, and we conspire by our joint effort to try to keep the plane stationary relative to the ground. Will the plane take off?
3) An airplane is sitting at rest on a very powerful treadmill. You are at the controls of the treadmill, while I am at the controls of the airplane. On some signal, I attempt to take flight in the plane, but you match my speed with the treadmill and keep me stationary relative to the ground. Will the plane take off?
Here are the absolute, 100%, bet-your-life-on-it answers to these rewordings:
Yes.
No.
Whoever asked this question is an idiot.
And that's about all this debate comes down to, folks. If we could all agree on one set of rules for the thought experiment, then we ought to be able to make the explanation of the answer clear. As it stands, normally one side has interpretation (1) in mind, and argues vehemently with someone else who has interpretation (2) in mind, and the whole thing blows up into a senseless squabble.
Here are the three core facts that are rock-solid:
A) If the plane remains stationary relative to the ground, it will not take off.
B) If the plane moves relative to the ground, it will take off.
C) The person operating the conveyor belt cannot by himself make the plane remain stationary relative to the ground.
(EDIT: Really, you should substitute the word "air" for ground in the above facts. I use "ground" throughout this post because of a consistent mistake made by "no-flys" in their assumption that the plane remains stationary. It doesn't remain stationary, relative to the ground or the air. The important point is that it moves relative to the air, not the ground, but I'm assuming throughout this post that there is no significant tailwind or headwind. I discuss the implications of this briefly in the section about windtunnels.)
That's about all you need to know to argue whichever interpretation is appropriate. I'll discuss why these facts are true in a moment. In the meantime, look back at the three re-wordings of the question above.
In (1), the key phrase is "you attempt to match my speed to try to keep me stationary." Since we know from fact (C) that you cannot keep me stationary, it follows from (B) that I will take off successfully.
In (2), we conspire together to keep the plane stationary. This is possible, albeit stupid. We know from fact (A) that I will not take off.
In (3) - and this is the important part - the actions being described are impossible. We know from (C) that the conveyor operator cannot keep the plane stationary. The most powerful conveyor belt in the world couldn't do it. David Copperfield couldn't do it. It can't be done. Only if the pilot "plays along" can the plane be made to remain stationary.
Unfortunately, most of the "no-flys" - the label given to those who argue that the plane won't take off - are assuming that interpretation (3) is what is being asked. They accept that the plane remains stationary, and say it won't take off. The "will-flys" know that the plane can't remain stationary, and say it will take off. Add to the mix a few people who see that in one way, the plane could be forced to be stationary by some pilot-conveyor cooperation, and you've got a deadly internet forum explosion cocktail.
Let's examine the physics behind the three key facts, so that there will be no doubt as to their validity. The first two are pretty easy to follow. Airplanes create lift by causing air to flow over their wings. This airflow is caused by the motion of the wings relative to the air - that can happen in two ways. The first way is to move the plane forward through the air. The second is to blow air against the plane and over the wings. As far as the plane is concerned, these two scenarios are equivalent. So you could put a plane in a very powerful wind tunnel, blow air over its wings, and have it fly stationary relative to the ground. But that's another question.
In our treadmill scenario, the air is stationary relative to the ground, so the plane has to move relative to the ground in order to gain flight. If it doesn't move, it simply won't fly. There will be no airflow over the wings, and there will be no lift. A lot of people get confused here, and think that the original thought experiment is some sort of trick question, and that the propeller of the airplane, or possibly the jet engines, will be blowing air backwards over the wings, which will create lift. While there will be a certain amount of airflow created by the propeller or engines, it is not enough to create flight. I promise you, that's not what the question is asking.
Really, I promise. Please, please stop talking about airflow created by the prop. It isn't part of the question.
So we have facts (A) and (B) well taken care of. If the plane moves, it flies. If it doesn't move, it doesn't fly. The real question is, will it move? Again, the answer is unambiguous - if the pilot doesn't try to make the plane stay still, it won't. If he does, it will. This is always, always the part that confuses people, so stick with me for a few more paragraphs.
When a plane is sitting on a runway, it moves by using its engines. It does not move by any sort of motorized wheel. The propellers or jets create thrust that pushes against the surrounding air and causes the plane to move forward. A plane wouldn't move at all in a vacuum chamber. Compare this to a car, which moves by applying torque to the wheels. A car would drive just fine in a vacuum chamber - at least, as long as the driver could survive (and technically, it would need some sort of air reservoir to provide something to mix with the fuel. An electric car wouldn't have this problem.) However, a car could not drive on a frictionless surface - imagine, for example, that you had your car on a super slippery frozen lake. As you hit the gas, the wheels would simply spin and spin in place, and the car wouldn't move forward. You may even have firsthand experience with this situation if you've ever gotten stuck in a snow bank. In contrast, a plane would have no trouble moving on a frictionless surface. The jet engines or propeller would still push against the air, and the plane would still move forward. If it were on a truly frictionless surface, then you would see the wheels sliding along the ground, not rotating.
I hope those two scenarios clearly illustrate the difference in motive force between cars and planes. Cars create their forward movement from torque applied to the wheels, which push against the ground and create forward motion from friction. Planes create their forward movement from thrust applied to the air, which pushes the plane forward regardless of the surface it is on.
Imagine a plane without wheels. The fuselage would sit on the runway, and as you fired up the engines, it would skid spectacularly along the runway, possibly spewing sparks in its wake and doing quite a number on the body of the aircraft. No matter how fast it was going, the frictional force against the airplane would be constant; friction does not depend on speed! If the engines were strong enough to get the plane up to the critical take-off speed, then it would still take off. The only reason planes have wheels is to reduce this sliding friction. The wheels roll along the runway instead of sliding, and the only friction that the plane feels is in the bearings of the wheels. This is substantially less than the friction that a sliding fuselage would create, and it's a much smoother ride for the passengers as well.
(Edit: Technically, there are some factors that would make the friction change with speed. The classic idealized model called "coulomb friction" doesn't really apply to bearings. As the bearings spun faster and faster, they would generate heat, which would increase the friction slightly on the wheels. However, it would never be enough force to prevent take-off. The only time this would prevent take-off is if the wheels locked up or broke off, and then we'd have a much bigger problem and catastrophic failure.)
So what does this all have to do with treadmills? Well, now let's place our plane on that treadmill and see what happens. If the wheels were perfect - that is, there is no friction in the bearings (and no deformation of the wheels as they spin) - then something interesting happens. When we turn on the treadmill, the plane stays stationary on its own. The wheels simply spin along the track, and impart no force to the plane. If you had a car with frictionless axles, and you disconnected the whole drive train, the same thing would happen to your car.
The only reason that a plane or a car moves backwards on a treadmill is that the wheels are somehow partially locked to the axles. In a plane, this is because of minor friction in the bearings. In a car, it's because of the drive train. If you want the car to stay still, you have to turn the drive train at the proper speed. If you want the plane to stay still, you have to overcome the minor bearing friction. And again, since friction does not change with speed, you don't have to exert any more force at higher speeds. If you run the treadmill at 5mph and turn on the plane's engines just slightly, they will provide enough thrust, pushing against the air, to keep the plane still. If you then increase the treadmill speed to 500 mph, you won't need to adjust the throttle on the airplane - it will remain stationary. That's because it's seeing the same frictional force that it was at 5mph. Thus, it doesn't matter how fast the treadmill is moving - if the pilot does not want to remain stationary, then he won't. It only uses the very first bit of power from the engines to keep the plane stationary. As the throttle is increased from that point, it moves forward just as it would on any other runway. It's pushing against the stationary air!
If you don't believe me, imagine this (or even try it at home): you're standing on a skateboard on a treadmill. You hold onto the handrails of the treadmill and turn it on. Of course, you'll remain stationary (relative to the ground). In fact, you only need to use a very light touch to stay stationary - perhaps a few fingers pressed against the handrails. Crank up the treadmill speed as high as you like. You'll still only need the same light touch to remain stationary. At any time you like, you can move forward - closer to the treadmill console - by simple pulling on the handrails. If you had a jet engine, or super-strong hairdryer, you could use this to propel yourself forward instead of holding onto the handrails. In fact, if you're really careful, you might be able to do this at home with a skateboard and a leafbower, but I doubt you'll have a sensitive enough control of your leafblower thrust to get yourself to remain stationary.
So you see (oh please tell me you see), the conveyor operator cannot force the plane to remain stationary. And if the plane isn't stationary, it can take off.
And yes, if we interpret the question in a different way, and assume that for some reason the pilot is colluding with the conveyor operator and keeping the plane stationary, then the plane can't take off.
But what is the question really getting at, anyway? There are really two "spirits" of the question. In the first, we're asking "can a plane take off with no runway, if I replace the runway with a treadmill?" The answer, as we know now, is no. The plane must move relative to the ground in order to take off. In another deep-meaning of the question, we're asking "is it possible to prevent a plane from taking off, by moving the runway backwards under it?" The answer again is no, you can't prevent it from taking off.
The interesting thing about all this is that in both scenarios, you'd wind up with a plane moving relative to the ground. In the first scenario, you might think you're being clever by allowing a plane to take off from a very small field, by using a treadmill runway. If you actually tried it, you'd be attempting to take off, so the plane would move, and would likely crash into something, or fall off a cliff, or suffer some other catastrophe that you were trying to avoid with questionable physics. In the second scenario, you'd give the plane plenty of room and safety to take off, but attempt to play a practical joke on the pilot by moving the runway backwards, and you'd wind up with a plane in flight, much to your chagrin.
When the "no-flys" saw the Mythbusters episode, they all complained that it wasn't done properly, because the plane didn't remain stationary. But think about it for a moment. No, really think about it, don't just spout about Bernoulli's principle and airflow and all that. In what possible scenario would the plane actually stay still? The only way this can happen is if the pilot is trying to stay still, and this only happens if he just barely applies the throttle, making no attempt to take off. This makes no sense. Either you're trying to prevent him from taking off with your clever and misinformed use of a conveyor belt, or he's trying to defy physics by taking off in a too-small area. There is no scenario in which the plane would realistically stay still. We know what would happen if it did - it would sit on the runway, not taking off, and we'd all stare at each other in an all-too-short silence punctuated by loud exclamations of "I told you so!". But that's not really what the thought experiment is getting at, no matter how you reasonably interpret it. Luckily for all of us, if we agree on the interpretation, reasonable or not, we should all agree on the answer.
So let's get back to the next great internet debate, shall we?
Think I'm right? Digg this site!
48 comments:
"Whoever asked this question is an idiot."
LOL. I just about dropped out of my chair in a fit of joy after reading this. Thanks for this article... perhaps there is hope for humanity afterall.
"On some signal, I throttle up the airplane and you turn on the treadmill, and we conspire by our joint effort to try to keep the plane stationary relative to the ground. Will the plane take off? No."
No amount of collaboration will prevent the plane from taking off. Given the existence of a free wheel between the treadmill and the plane, the treadmill is incapable of applying any horizontal force to the plane. It cannot slow the plane down.
"No amount of collaboration will prevent the plane from taking off. Given the existence of a free wheel between the treadmill and the plane, the treadmill is incapable of applying any horizontal force to the plane. It cannot slow the plane down."
The plane can always not take off, if the pilot doesn't want it to. If its forward thrust matches the force of friction it will remain stationary. If by "free wheel" you mean frictionless then the pilot doesn't apply any thrust at all and the plain remains stationary.
Ok, I can agree to that. As long as we're clear that in #2 you're arguing a deep corner case. That is, the pilot purposely fails to overcome the (relatively) small friction in the axles of his wheels with the engines, in some cases by keeping them shut off. Of course, you can say the same thing about a runway without a treadmill.
If the pilot wanted to take off, he could.
"If the pilot wanted to take off, he could."
Agreed.
I once saw a UFO take off from a treadmill. I've never been the same.
Simplest way for me to think about it is Newton's laws. You apply a force, F, to the plane with the prop. Its mass, m, relative to the ground, must accelerate, since F is the only force acting along the horizontal axis. F=ma, so eventually it must reach takeoff speed because it is accelerating relative to ground.
I fully agree with the people who said that in situation #2 the pilot would have to keep the engines on stand-by or even shut off, in which case the presence or absence of a conveyor belt doesn't even begin to enter into the equation, at least not for practical purposes.
In the discussion over on kottke.org, I explained it like this:
> "and we conspire by our joint effort to try to keep the plane stationary relative to the ground. Will the plane take off? No."
The conclusion would be correct assuming that premise, but the premise is surreal. In order to keep the plane stationary relative to the ground, the pilot wouldn't be allowed to turn on the engines in the first place. Once they're running and generating thrust, the c-belt operator can't do anything to hold the plane in place. (Except in those situations, already mentioned by many posters, in which the belt would accelerate beyond light speed in a microsecond and the universe violently implodes, or something like that. Which obviously neither works in a thought experiment with ideal, friction-less wheels, nor in the real world.) Note that you can 'prove' anything when you start out from a wrong premise. Consider the following statement: "If the circumference of a circle equals its radius, then the pope is a Protestant." Think about it. It's true, literally!
"In the first, we're asking "can a plane take off with no runway, if I replace the runway with a treadmill?" The answer, as we know now, is no. The plane must move relative to the ground in order to take off."
Not in a good enough headwind!!
Being an MD, PhD, and a Scientologist, I consider myself an expert on everything.
1) The very idea that this Chris character decided to spend so much time on the subject makes me violently angry. It is obvious that the plane will take off, lest the pilot match the applied force of the engines to friction force from the ground. If you needed to read this entire post to get that, you might want to forget how to breath.
2) Find me a perfect frictionless bearing that will allow the plane to remain stationary on a treadmill, and I will pull a leprechaun out of my rear end. Frictionless is a concept used to make physics problems simpler. It is near impossible to create frictionless conditions in the really real world.
The biggest problem with this thought experiment, is that many of the wordings make the assumption that the plane does, in fact, remain stationary. Since this is worded as a part of the statement, and not the question, people do not question it, and assume the statement is correct. Therefore, the plane would not take off, because it's stationary. This assumption is further assisted by images such as this one, when posing the question "will it take off?" http://farm1.static.flickr.com/134/336644021_adf0c4a276_m.jpg
Since the plane is shown on a treadmill only as long as the fuselage, and there is a barrier to keep it from rolling -off- the treadmill, it seems a valid enough assumption that the plane must not be moving, and this assumption is translated to the question, "Will it take off?"
In this case, it couldn't because the wings would hang on the treadmill - but that's just an interpretation of the image.
"The biggest problem with this thought experiment, is that many of the wordings make the assumption that the plane does, in fact, remain stationary."
That would be interpretation (3) in the original post, answered by the authoritative "Whoever asked this question is an idiot."
Simplify. There are 2 interpretations to this question:
1. If you keep the plane from moving, will it be able to take off?
Clearly, the answer is "NO". Movement is necessary to generate airflow and thus lift.
2. Will the treadmill be able to keep the plane from moving, and thus prevent it from taking off?
The answer to number 2 is also "NO". This seems to be the question that most people fail to understand, but the proofs have been posted so I will not repeat them.
The treadmill cannot prevent the plane from moving. It will gain airspeed and thus generate lift, and will fly.
A good quote I came across somewhere:
"The plane is not magically levitating while standing still. It is moving forwards as usual, and ignoring what the ground underneath it is doing. Which is the entire point of having a plane, really."
Is it really true that an airplane moves forward by "pushing against the surrounding air"?
Isn't it really that the forward thrust is generated by the "equal and opposite reaction" of the action of throwing stuff backwards (like air or spent fuel)?
An airplane in a vacuum chamber couldn't move forward, because there is no air to throw backwards.
Unless it was rocket propelled. No air needed in that case.
Is it really true that an airplane moves forward by "pushing against the surrounding air"?
That is a simplification, but yes it's true.
Isn't it really that the forward thrust is generated by the "equal and opposite reaction" of the action of throwing stuff backwards (like air or spent fuel)?
Yes, that's correct. But what is an airplane engine pushing backwards? You said it yourself - air! It's pulling the surrounding air into the engine, and then pushing that air backwards to generate thrust. The fact that there is "spent fuel", or exhaust, in that air now is of little to no consequence.
An airplane in a vacuum chamber couldn't move forward, because there is no air to throw backwards.
Unless it was rocket propelled. No air needed in that case.
True, but no air also means no combustion, so the engine couldn't run anyway. And rockets, believe it or not, actually carry their own "air" with them, in the form of an oxidizer, so they are still pushing air backwards in order to generate thrust forwards.
thank you thank you thank you. now lets see jamie and adam fly a plane in a wind tunnel.
...we conspire by our joint effort to try to keep the plane stationary...
#2 is a specious argument. The only way the plane can remain grounded is to have the pilot purposely powering down his engine, or even never turning the engines on. If this is the case, why even get the pilot out of bed for the experiment? Why use a plane with working engines?
The simplest way to bust this "myth" is to look at the implications of the original question.
It says that the conveyor belt must match the speed of the plane.
What speed? If the plane stays stationary, there is no speed.
To have speed, the plane must already be moving and thus it cannot stay stationary.
Yeah, if you could add a slight edit in your post it would be perfect. Where you mention a vacuum preventing a plane from taking off, a rocket engine could take off even in a vacuum. (I just don't want anyone to be able to poke holes in your explanation ;)
Some figures would be nice but I'm having trouble trying to think of any. I'll send some if I can.
It turns out it _is_ possible for the conveyor operator to keep the plane stationary, but not by matching "speed"; and to do it indefinitely you need a conveyor that can accelerate indefinitely.
See http://www.straightdope.com/columns/060303.html for the details.
So, the thrust of your post is correct w.r.t. the original (silly) question, but your supporting assertion that it is fundamentally impossible for _any_ action on the conveyor's part to prevent the plane from moving is not correct.
you need a conveyor that can accelerate indefinitely.
The original question required the speed of the belt to match the speed of the plane. Accelerating the belt to infinity breaks this condition.
"to do it indefinitely you need a conveyor that can accelerate indefinitely."
In other words, no. You can't keep the plane from taking off.
You can't accelerate the conveyor belt past the speed of light, which means you can't stop the plane from taking off.
What a silly argument.
DUFF has it right... there's two different understandings of the problem:
1) can a plane achieve flight from a stationary position relative to earth, but in motion relative to the treadmill?
2) can the force of the plane overcome the force of the treadmill?
the treadmill is intended as a device that keeps the plane from moving forward, assuming that the plane behaves on the treadmill the same as a car would. but it doesn't. and that sets up problem number 2.
the 1st understanding of the problem is a question about what generates lift. the 2nd understanding of the problem is a question about the origin of force and the influence of friction.
My analysis:
Plane on a Conveyor Belt Takes Off!
As predicted, of course. The Mythbusters proved it in last night's show.
There has been lots of discussion on the internet about whether an airplane on a conveyor belt could take off, if the conveyor belt moved in the opposite direction at the same speed as the airplane. The problem is usually stated something like this:
"A plane is standing on a runway that can move (some sort of band conveyor). The plane moves in one direction, while the conveyor moves in the opposite direction. This conveyor has a control system that tracks the plane speed and tunes the speed of the conveyor to be exactly the same (but in the opposite direction). Can the plane take off?"
The people who say no, typically reason that for an airplane to take off, it needs airflow over the wings (more than just the amount the propeller blows), but since the airplane can't move forward, there is no airflow over the wings, therefore the airplane can't take off.
But this begs the question. Of course the airplane needs to move forward at a speed great enough to supply the lift in order to take off. That's kind of integral to the idea of "taking off." Whether the airplane can do so is exactly the question we are being asked, I think.
The faulty assumption is that the contraption is designed to prevent the airplane from gaining forward speed. That, however, is not stated in the problem. People make this assumption, I guess, by analogy to walking on a tread mill where one does not go forward, but stays in one spot as the treadmill goes backward at the same speed one is walking forward.
But airplanes don't propel themselves forward by pushing against the ground (or the treadmill in this case) like walking people or cars do. Airplanes' forward thrust comes from the "equal and opposite reaction" of the action of throwing stuff backwards (air, in the case of a propeller plane, or the hot expanding gases of spent fuel in the case of a rocket).
It amazes me that so many people just don't get it, even after having it explained and demonstrated. Many of them claim that the Mythbusters experiment was flawed, because "the plane actually did move forward!" For some reason, they thought that the "wheel speed" of the plane was to match the conveyor belt speed. But the original question only says that the speed of the conveyor belt matches the speed of the plane.
The assumption that the "speed of the plane" means it's wheel speed relative to the belt is an unwarranted assumption, in my opinion. Unwarranted, because it makes the original question illogical. The only way for the wheel speed to match the belt speed is for neither the plane nor the belt to be moving at all; or for the plane's engines to be providing just enough thrust to match the very minimal force of the wheel friction in order to keep it from being dragged backwards. But the question is, "can the plane take off?" This implies that the plane is trying to take off, which means full thrust, not just minimal or no thrust. So it must be that the "speed of the plane" must be relative to the ground.
Wow
I'd never even heard of this debate until now, and i have to say at first, i was on the stupid end of the stick but your explanation was very to the point, and it cleared it right up for me.
and while i felt kind of stupid for getting it wrong at first: (no it can't take off! durrr!) I have to say this is a really elegant thought puzzle. unless you realise where the actuall force is comming from and being applied, your stuck in your own stupidity. good post
"Here are the three core facts that are rock-solid:
...
C) The person operating the conveyor belt cannot by himself make the plane remain stationary relative to the ground."
This is true for planes with wheels and achievable speeds on conveyor belts. The friction with the ground is very small.
However, if the plane has skis or pontoons (on the ground) or you allow the conveyor speed to be unbounded then friction can increase to a degree where it is possible for the conveyor operator to keep the plane grounded.
"or you allow the conveyor speed to be unbounded then friction can increase to a degree where it is possible for the conveyor operator to keep the plane grounded."
In theory, the speed at which the wheels are turning should not increase the force of friction. That is, an ideal wheel would not be affected by the speed. Of course, in the real world, the mechanics of the wheel would break down at high enough speeds and the friction would increase to the point where either the plane would slow down and stop, or the wheels would snap off. Of course, these speeds would be pretty astronomical, and I doubt any treadmill in the real world would be able to withstand those speeds itself.
However, even if we allow an 'ideal wheel' there is still a purely hypothetical scenario where the treadmill could keep the plane stationary. If the treadmill is allowed to have unbounded speed and unbounded acceleration, then I believe the rotational inertia would also be unbounded, because it can be expressed as a function of the acceleraion of the treadmill. And if the rotational inertia is unbounded then the force it exerts on the plane is also unbounded, and the plane could be forced to remain stationary.
....Aaactually, now that I think about it, the friction between the wheel and the treadmill would probably not be great enough, and when the rotational inertia started to build against the turning of the wheel, the wheel would just start to slide along the treadmill.. and the plane would still move forward.
I have FAITH that it won't take off...you're persecuting my religion!!1!11
Seriously though, well done. You've gathered a coherant collection of arguments (none of which should really have been required if you ask me...). There's still gonna be people complaining though. Some people simply can't admit that they are wrong (I think the largest source of confusion is people mistaking the wheels on a car [driven] with the wheels on a plane [freewheeling]).
"So what does this all have to do with treadmills? Well, now let's place our plane on that treadmill and see what happens. If the wheels were perfect - that is, there is no friction in the bearings (and no deformation of the wheels as they spin) - then something interesting happens. When we turn on the treadmill, the plane stays stationary on its own. The wheels simply spin along the track, and impart no force to the plane. If you had a car with frictionless axles, and you disconnected the whole drive train, the same thing would happen to your car."
This part is not true unless you are talking about massless as well as frictionless wheels. The wheels' rotational inertia will resist the treadmill and will apply a backward force on the airplane as the treadmill is accelerating.
Oh, if I could only sage, I would sage you to deletion and beyond.
RAAAAAAAAAAAAAAAAAAGE
Alright, so we've got a 747 sitting at rest on a hypothetical uber-treadmill. the engines fire up, and the plane starts to roll forward.
then the treadmill starts rolling backwards at an equal amount to keep the plane geographically stationary.
guess what guys - the whole reason a plane has engines is so it can move the damn wings through the air, as its the movement of the air over the wings that provides lift.
if there's not sufficient wind flowing over the wings..
....guess what...
IT WONT FLY.
then the treadmill starts rolling backwards at an equal amount to keep the plane geographically stationary.
siztem, did you even READ the webpage? The whole point is that the plane doesn't remain geographically stationary. It doesn't matter how uber your uber treadmill is.
...guess what...
IT WILL FLY.
A 747 taxies to the threshold and lines up, ready for take-off. Each set of wheels sits on a conveyor belt which is free-moving (i.e. not driven and, for the sake of this hypothetical, completely friction-less). Light the fires. Accelerate to take-off thrust. Forward thrust is created but the heavy body doesn't move - just spins its wheels. Just like an engine test bed situation, except the engine isn't tethered down. The thrust has instead been converted into spinning a conveyor belt.
What's happening inside the cockpit? OttoPilot has pushed his thrust levers fully forward. He hears the scream of the engines, but the world outside isn't moving. What does the ASI read? Zip. Because there's no movement through the air.
No airspeed? No lift.
That 747 isn't going anywhere. Least of all up.
Same 747 at the threshold, mains are sitting on the conveyor belts. Engines are off. This time OttoPilot is staring at a whacking great big fan sitting on the runway in front of the nose. The fan starts up with a whirr. Faster and faster it spins, pushing air at OttoPilot and his 747. The heavy bird would move backwards because of the force of the air pressure, but instead the wheels spin backwards on the free-moving belt. Otto looks out of his window, but no movement is discernable. He looks at his ASI. Wow! The needle moves! As the fan speeds up even more, the ASI creeps upwards until - lo and behold! - takeoff speed is reached. With a slight judder, the wings produce enough lift to raise the wheels off the belt. Flying! No engines! WTF?
Grahame said: "... the heavy body doesn't move - just spins its wheels...."
It doesn't spin its wheels. A CAR would spin its wheels, because a CARs engine drives the wheels. A planes engines, however, DO NOT DRIVE THE FUCKING WHEELS. A plane, effectively, pushs itself off from the air behind it. It takes off.
Eoin, yes...engine thrust does not directly power the wheels. Agreed.
1. We know that the engine produces thrust. Undisputed.
2. Engine is attached to plane. Engine thrust directed rearwards. Because of equal and opposite reaction, plane wants to move forward.
3. Thrust develops until it overcomes inertia of the body. As it overcomes that inertia, thrust is then greater than all the forces holding the body to the ground. Something must happen. If the plane's wheels were on concrete, the wheels would enable it to move forward, acting as bearings between two solid bodies, the plane and the ground, converting engine thrust into movement. But now instead of the ground, we have a free-wheeling conveyor belt.
Thrust is therefore converted into movement of the belt (which can be connected via an axle to a belt-driven generator to supplement Eskom's deficiencies - a jumbo electricity supply. Probably still cheaper than accepting quotes from all the power station smouse now flocking to the scene of the disaster).
Plane can't fly. So where is my layman's logic wrong. Help please.
Sorry, please ignore comments about Eskom - this is a reference to a South African power supply issue.
A 747 taxies to the threshold and lines up, ready for take-off. Each set of wheels sits on a conveyor belt which is free-moving (i.e. not driven and, for the sake of this hypothetical, completely friction-less). Light the fires. Accelerate to take-off thrust. Forward thrust is created but the heavy body doesn't move - just spins its wheels.
INCORRECT!!
If the belt is unpowered, it won't move at all. The plane will roll along the belt just as well as along the ground. Now, if the belt is truly frictionless, as you say, and the wheels have any amount of friction in the bearings, the belt will actually move forwards (ie, in the same direction as the plane), but very slowly (since it's only being accelerated by a very minor frictional force in the wheel bearings), and the wheels will roll faster along the belt, causing forward motion of the plane.
Same analogy with the home treadmill and skateboard again - if you stand on a skateboard (or rollerskates) on a treadmill, and pull yourself forward by using the handrails, it doesn't make the belt spin under you, does it? Even if the belt was completely frictionless, surely, surely, you would move. Do you believe that you would be pulling on the handrails as hard as you could, and magically the belt would be spinning underneath you? Of course not! As soon as you pull on the handrails, you will move, regardless of what the belt under you is doing. The plane is doing exactly the same thing, but its handrails are made of stationary air.
The plane will move. I promise.
Chris, I see the light! Hallelujah! Why, though, isn't yet clear. But the analogy of the roller skates on the treadmill made intuitive sense.
Grahame: "...Thrust is therefore converted into movement of the belt..." is where your laymans logic went wrong. The statement is false.
Glad you've seen the light...although the skateboard analogy in the original post really should have made it clear for you...
Graham, the easiest way to picture it for me is if you consider the plane to have super-slick near-frictionless skiis on the bottom, instead of wheels. The wheels thing messes people up because they are used to cars. When you compare the wheels on a plane to skiis, its easy to see that they both serve the same purpose... simply that of reducing friction.
If a plane with super-slick skiis is on a fast-moving treadmill, as long as the thrust of the engine is enough to overcome the friction between the skiis and the treadmill, the plane will accelerate forward to take-off speed. The same is true of a plane with wheels. Wheels are just better at reducing friction than skiis.
All 3 of his interpretations are incorrect because he is measuring the plane speed relative to the conveyor belt, then measuring the conveyor belt speed relative to the ground, then comparing the two speeds measured in different reference frames.
The question does not specify how speeds are measured. But there is no common speed dial on a plane that measures speed by the rotation of the wheel, and the general rule for every situation is to measure speed relative to the Earth (the ground).
Chris,
This site is great! You finally disassemble each side of the argument in a well-thought out article. And yes, I know that the plane takes off (given the original wording of the question).
A long time ago, I was thinking of explaining this whole question in different terms (on the ebaumsworld forum, of course). I'd explain what was meant by "speed of the airplane" and "speed of the treadmill" (as an anonymous poster mentioned above). That is, I'd explain what effects each of the 9 different cases of reference points (or 4 if you consider air and the stationary ground to be equivalent frames of reference) had on the interpretation and the potential answers to the original question.
So let's break it down to just 4 cases for the sake of brevity. The 3 reference points I'm using are airplane, treadmill, and ground (== air). Because an object has 0 speed relative to itself, I won't consider those cases.
1. The airplane's speed is relative to the ground, and the treadmill's speed is relative to the ground.
2. The airplane's speed is relative to the ground, and the treadmill's speed is relative to the airplane.
3. The airplane's speed is relative to the treadmill, and the treadmill's speed is relative to the ground.
4. The airplane's speed is relative to the treadmill, and the treadmill's speed is relative to the airplane.
Case 1 is the most likely interpretation of "speed" for the airplane and treadmill. The reference point is the same for both, so the answer must be "yes", the plane takes off (with little difference from a normal runway takeoff, even).
Case 2 doesn't seem like a good interpretation of "speed" for the treadmill; who would measure the treadmill's speed relative to the airplane? If you did, you would see that it's impossible to keep the speeds the same but opposite except at a speed of 0. But as the original question stated, the plane does in fact move. This case is not possible, and fortunately it's not a popular interpretation of "speed".
Case 3 is similar to case 2, in that the plane must not move for the condition that the speeds must match for the treadmill to do its job. Besides, nobody measures the speed of an airplane by its wheels, and normally an airplane doesn't use the runway below it to measure its speed; an airplane's speed is measured by the air flowing past it, which (I think) can be assumed to be the same as the speed over the stationary ground.
Case 4 is always true by law, as two objects' speeds relative to each other are always equal but opposite. That's a given. Of course, as in case 3, nobody measures the plane's speed with its wheels (which is its speed relative to the treadmill); as in case 2, nobody would measure the treadmill's speed relative to the airplane. So case 4 is right out. (The plane can take off as normal in this case—the runway could move at any speed w.r.t. the ground and the airplane moves as normal, alse w.r.t. the ground/air—but it should be obvious that this interpretation is a silly one).
I think most people use case 3 to argue that the plane does not take off, and in fact you (Chris) don't make it clear that this is not a good set of reference points to use. Case 1 seems the better interpretation of the two, and it's easy to explain that it takes off if a common reference point (the stationary ground) is used to measure the two speeds.
"If the plane remains stationary relative to the ground, it will not take off."
If you want to bury every shred of the no-fly argument, you can counter that statement. It is possible to design a plane that will take off with its brakes on, just from propwash alone. Just give it freakishly huge flaps. It won't fly very well, but on takeoff, it can pop itself straight upward. Nobody's built a physical plane that does it, but there have been a few designs that work in X-plane, a very accurate flight simulator.
Of course, there are many real-life examples of VTOL, but I'm sure the no-fly folks won't accept VTOL as an answer to the question.
Thanks...
Caltel
Article
圣诞树 小本创业
小投资
条码打印机 证卡打印机
证卡打印机 证卡机
标签打印机 吊牌打印机
探究实验室 小学科学探究实验室
探究实验 数字探究实验室
数字化实验室 投影仪
投影机 北京搬家
北京搬家公司 搬家
搬家公司 北京搬家
北京搬家公司 月嫂
月嫂 月嫂
育儿嫂 育儿嫂
育儿嫂 月嫂
育婴师 育儿嫂
婚纱 礼服
婚纱摄影 儿童摄影
圣诞树 胶带
牛皮纸胶带 封箱胶带
高温胶带 铝箔胶带
泡棉胶带 警示胶带
耐高温胶带 特价机票查询
机票 订机票
国内机票 国际机票
电子机票 折扣机票
打折机票 电子机票
特价机票 特价国际机票
留学生机票 机票预订
机票预定 国际机票预订
国际机票预定 国内机票预定
国内机票预订 北京特价机票
北京机票 机票查询
北京打折机票 国际机票查询
机票价格查询 国内机票查询
留学生机票查询 国际机票查询
I think your model is missing a force: you mention the friction of the wheel bearings, but omit the rolling resistance force created by friction between the wheel and the ground.
Doesn't change the fact that the plane will take off, though.
However, I'm interested in the hypothetical case in which the conveyor belt speed is unlimited (and the wheels are indestructible). . .trying to figure out the math required to compute the conveyor belt acceleration (and the energy input) required. . .
PS-- I'm thinking that a rocket doesn't generate thrust by pushing "air," if you're referring to the oxidizing agent. . .it pushes whatever the byproduct of combustion is, the exhaust (thrust = exhaust mass * rate at which it's expelled). . .
It doesn't have to be air int he 79%N/21%O sense of earth's atmosphere. It is a mass of various gasses, including CO2 and other waste products. As I said in my original post, rockets carry their own oxygen with them for combustion, so in a sense it is still air that they exhaust.
Post a Comment